a+b)^n=∑_(k=0)^n ▒(n¦k)a^k b^(n-k)1/2π ∫_0^2π ▒ⅆθ/(a+b sin θ)=1/√(a^2-b^2)lim_(n→∞)〖(1+1/n)^n〗=ex=(-b±√(b^2-4ac))/2a
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